10n^2+29n-15=0

Solution for 10n^2+29n-15=0 equation:

10n^2+29n-15=0

a = 10; b = 29; c = -15;
Δ = b2-4ac
Δ = 292-4·10·(-15)
Δ = 1441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{1441}}{2*10}=\frac{-29-\sqrt{1441}}{20}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{1441}}{2*10}=\frac{-29+\sqrt{1441}}{20}
$